Stark Effect in Hydrogen

Consider a single electron in the n = 2 state of the hydrogen atom. We ignore relativistic corrections, so the 2s and 2p states are initially degenerate. Then we impose a small static electric field E = |E|ẑ. Use perturbation theory to derive how the n = 2 energy levels are changed to lowest order in powers of |E|.

SOLUTION

We use the notation |LM⟩ to describe the four orbital states: the s-state is |00⟩ and the three p-orbitals are |1 – 1⟩, |10⟩, |11⟩. Spin is not affected by this perturbation and plays no role in the calculation. For degenerate perturbation theory we must evaluate the 10 different matrix elements ⟨LM|V(z)|L'M'⟩ which occur in the symmetric 4 × 4 matrix. The interaction potential is V = -e|E|z. One can use parity and other group theory arguments to show that only one matrix element is nonzero, and we call it ξ:

(1)

Since the two states | 1 ± 1⟩ have no matrix elements with the other two states, we can omit them from the remaining steps in the calculation. Thus we must find the eigenvalues of a 2 × 2 matrix for the states |00⟩ and |10⟩.

(2)

This matrix has eigenvalues λ = ±ξ. The perturbation splits the fourfold degenerate n = 2 state into states with eigenvalues

(3)

Since is proportional to the electric field, the energies split linearly with |E|.

The matrix element ξ can be evaluated by using the explicit representation for the n = 2 eigenstates of the hydrogen atom:

(4)

(5)

yielding

(6)

The angular integral gives 2/3, and s = r/a₀.

مواضيع ذات صلة

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