Osmotic Pressure

Consider an ideal mixture of N₀ monatomic molecules of type A and N₂ monatomic molecules of type B in a volume V.

Figure 1.1

a) Calculate the free energy F(τ, V, N₀, N₁). Calculate the Gibbs potential G(τ, P, N₀, N₁). G is the Legendre transform of F with respect to V.

b) If N₀ >> N₁ the molecules of type A are called the solvent, and those of type B the solute. Consider two solutions with the same solvent (type A) and different concentrations of solute (type B molecules) separated by a partition through which solvent molecules can pass but solute molecules cannot (see Figure 1.1). There are N₀ particles in volume V (or 2N₀ in volume 2V), and N₁ and N₂ particles in volume V on the left and right of the membrane, respectively. Calculate the pressure difference across the membrane at a given temperature and volume. Assume that the concentrations of the solutions are small; i.e.,

and

SOLUTION

a) The free energy for a one-component ideal gas is

(1)

The Gibbs free energy

(2)

But G = G(τ, V, N), so (2) must be transformed:

(3)

If we have a mixture of two types of molecules with N₀ and N₁ particles each, we find for the thermodynamic potential of the mixture:

(4)

Therefore  The Gibbs potential of the mixture

(5)

where P₀, P₁ are partial pressures (P = P₁ + P₂) corresponding to particles A and B, respectively. So,

(6)

It can be seen that

namely

(7)

where N = N₀ + N₁.

b) To derive the pressure difference, we notice that for the system with a semipermeable membrane, only the chemical potentials of the solvent are equal, whereas the chemical potentials of the solute do not have to be (since they cannot penetrate through the membrane). We will write first the Gibbs free energy on the left and right of the membrane,  and  respectively. will be defined by (6), with P → P_L, whereas

(8)

The chemical potentials of the solvent are given by

(9)

Equating μ_R = μ_L, we obtain

(10)

or

(11)

where we only take into account the first-order terms in the solute. If we also assume, which is usually the case, that the osmotic pressure is also small, i.e.,  we obtain, from (11),

(12)

where C₁ and C₂ are the concentrations of the solutes: C₁ ≡ N₁/N₀; C₂ ≡ N₂/N₀. Therefore, with the same accuracy, we arrive at the final formula:

(13)

A different derivation of this formula may be found in Landau and Lifshitz.

مواضيع ذات صلة

مصطلحات الفيزياء النووية

إزاحة حمراء REDSHIFT

المركبات النانوية (Nanocomposites)

مولد فان دي جراف الالكتروستاتي

التطويرات التقنية الحديثة في المعجلات الالكتروستاتية

معجلات الالكترونات الالكتروستاتية

معجلات الفان دي جراف الترادفية

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