 
					
					
						Conservation of Linear Momentum					
				 
				
					
						 المؤلف:  
						Professor John W. Norbury
						 المؤلف:  
						Professor John W. Norbury					
					
						 المصدر:  
						ELEMENTARY MECHANICS & THERMODYNAMICS
						 المصدر:  
						ELEMENTARY MECHANICS & THERMODYNAMICS					
					
						 الجزء والصفحة:  
						p 116
						 الجزء والصفحة:  
						p 116					
					
					
						 28-12-2016
						28-12-2016
					
					
						 2573
						2573					
				 
				
				
				
				
				
				
				
				
				
			 
			
			
				
				Conservation of Linear Momentum
If all the external forces are zero (Σ ext = 0) then
ext = 0) then  which implies that the total momentum
 which implies that the total momentum
  (1.1)
     (1.1)
Note that this is only true if all the external forces are zero. Halliday calls this a closed, isolated system. Another way of stating (1.1) is
  
Remembering that  is the total momentum of a system of particles (
 is the total momentum of a system of particles (
 ), the conservation equation is
), the conservation equation is
  
This is a vector equation, so we must always write it out in x, y, or z components.
Example A rifle of mass mR fires a bullet of mass mB which emerges at a speed of vBf . With what speed does the rifle recoil ?
Solution The bullet-rifle system is a closed, isolated system. When the rifle is held at rest the sum of all external forces is zero. Thus momentum is conserved for the bullet (B)-rifle (R) two body system. The total momentum is  , so that conservation of momentum is
, so that conservation of momentum is
  
Now this is a vector equation, so it must be written in terms of components, namely
  
but there is only motion in the x direction and nothing is happening in the y direction, so let's re-write the x-equation, leaving off the x's as

or

But vRi + vBi = 0 because before the gun is fired (initial situation) the bullet and gun do not move. After the gun is fired (final situation) they both move. Thus

where the minus sign indicates that the rifle moves in a direction opposite to the bullet.
				
				
					
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