Gravitation Near Earth's Surface

Newton's formula  is often called the law of Universal Gravitation because it applies to all bodies in the universe. How does it fit in with our concept of Weight which we defined to be the gravitational force at the surface of the Earth, namely

where g = 9.8 m sec^-1 is the acceleration due to gravity at the surface of the Earth? Well, if  is universal then it should predict the Weight force. Let's see how this comes about.

Example Show that  gives the same result as W = mg near the surface of Earth.

Solution Let m₁ ≡ M be the mass of Earth, which is m₁ = M = 5:98 × 10²⁴ kg. Let m₂ ≡ m be the mass of a person of weight W = mg. The distance between the centers of the masses is just the radius of Earth, i.e. r = 6370 km (which is about 4000 miles, only slightly larger than the width of the United States or Australia). Thus the gravitational force between the two masses is

which is the same as W = mg. In other words we have predicted the value of g from the mass and radius of Earth. You could now do the same for the other planets.

Example Explain how to measure the mass of Earth.

Solution In the previous example, we found

where M is the mass of Earth and r is the radius of Earth. Thus by measuring g (which you do in the lab) and by measuring r (which the ancient Greeks knew how to do by comparing the depth of a shadow in a well at two different locations at the same time) then M is given by

and G was measured in the famous Cavendish experiment (look this up).

مواضيع ذات صلة

أنظمة لأكثر من جسيم واحد

كمية التحرك الزاوية والقوة المركزية

الحركة الدورانية

امثلة عن الاتزان الاستاتيكي للأجسام الممتدة

الاتزان الاستاتيكي للأجسام الممتدة

تعريف العزم

تذبذبات صغيرة لبندول

اعتبارات الطاقة في الحركة التوافقية البسيطة

الحل الهندسي للمعادلة التفاضلية للحركة التوافقية البسيطة، دائرة المرجع

الحل باستخدام حساب التفاضل والتكامل

قانون هوك والمعادلة التفاضلية للحركة التوافقية البسيطة

القدرة ووحدات الشغل